Fractals

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A power of 4 IFS Julia at point:

.575 + .06 * I

With the following weights:

if (r < .9)

{

z = // root 0

}

else if (r < .95)

{

z = // root 1

}

else if (r < .98)

{

z = // root 2

}

else

{

z = // root 3

}

The weights are getting harder and harder to find as the power increases!

https://plus.google.com/101799841244447089430/posts/FLhBuNMgRci

#Fractal #IFS #Julia #Art #Math

.575 + .06 * I

With the following weights:

*______________________________*if (r < .9)

{

z = // root 0

}

else if (r < .95)

{

z = // root 1

}

else if (r < .98)

{

z = // root 2

}

else

{

z = // root 3

}

*______________________________*The weights are getting harder and harder to find as the power increases!

https://plus.google.com/101799841244447089430/posts/FLhBuNMgRci

*__*#Fractal #IFS #Julia #Art #Math

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I GOT IT!!!!! Doing a little dance... Finally! I thought it would be damn near impossible. Well, I guess the lesson is: NEVER GIVE UP!

Wow. Here is the formula:

z = pow(z, 3) - (pow(-z, 2.00001) - 1.0008875);

I am VERY happy! I just needed to calm the heck down and: Think. I guess another lesson is, try not to work when you are nervous. Damn it!

https://plus.google.com/101799841244447089430/posts/T7eShMwTMVK

#Fractal #Julia #Cubic #Art #Math

Wow. Here is the formula:

z = pow(z, 3) - (pow(-z, 2.00001) - 1.0008875);

I am VERY happy! I just needed to calm the heck down and: Think. I guess another lesson is, try not to work when you are nervous. Damn it!

https://plus.google.com/101799841244447089430/posts/T7eShMwTMVK

*__*#Fractal #Julia #Cubic #Art #Math

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A power of 3 inverse iteration Julia at point:

-.5 + .06 * I

With the following weights for the three roots:

if (r < .0333333333333)

{

z = // root 0

}

else if (r < .766666666666)

{

z = // root 1

}

else

{

z = // root 2

}

Fairly decent detail in the spirals...

;^)

#Fractal #Julia #Art #Math

-.5 + .06 * I

With the following weights for the three roots:

*______________________________*if (r < .0333333333333)

{

z = // root 0

}

else if (r < .766666666666)

{

z = // root 1

}

else

{

z = // root 2

}

*______________________________*Fairly decent detail in the spirals...

;^)

*__*#Fractal #Julia #Art #Math

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My cubic Julia in Xaos. So far, I have it working fine in several of my C and C++ programs, along with Xaos. I need to get it to work in Ultra Fractal damn it! I am a newbie in that program. Fwiw, the formula from that works in Xaos is:

Z^3 - ((-Z)^2.00001 - 1.0008875)

https://plus.google.com/101799841244447089430/posts/ASbWXo8Da6g

#Fractal #Cubic #Julia #Math #Art

Z^3 - ((-Z)^2.00001 - 1.0008875)

https://plus.google.com/101799841244447089430/posts/ASbWXo8Da6g

*___*#Fractal #Cubic #Julia #Math #Art

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