## Profile

Jason Hartgraves

22 followers|64,331 views

AboutPostsPhotosYouTubeReviews

## Stream

### Jason Hartgraves

Shared publicly -How Vectors (physics and mathematics) in 3-dimension work

Given two vectors in three dimensions, one can define their vector or cross product as new vector, perpendicular to both original vectors, and with magnitude proportional to the sine of the angle from the first to the second vector.

In this animation, the cross product of two vectors a (blue) and b (red) are used, and their cross-product (vertical, in purple) is shown varying as the angle between both vectors changes.

As you can see, when both vectors are separated by a right angle (90° = π/2 radians or τ/4 radians), their cross product’s vector reaches a maximum length, and when both vectors are parallel, their cross product is zero. (Here, both vectors a and b are unit vectors, so the magnitude of their cross product doesn’t grow beyond 1 either)

Similar to the way the dot product can be used to find if two vectors are perpendicular, one can use the cross product to find out if two vectors are parallel. You just have to check if these products are zero in each case.

The mathematics

In mathematical notation, we write |v| or ||v|| as the norm or magnitude of a vector v. With that notation, we can say that |a × b| = |a| |b| sin(θ)

, where θ is the angle from a to b.

The cross product is said to be “anticommutative”, that is, the order used is important (so it is not commutative, in which case the order wouldn’t matter), and the “anti-” bit says that switching the order switches the sign of the product. Mathematically, a × b = -(b × a)

To be precise, the vector that results from the cross product is said to be a pseudovector, as it is not invariant through reflections: if you see your coordinate axes from a mirror, your right-handed coordinate system would become left-handed, so the definition of the vector breaks down. Vectors are extremely useful because they don’t depend on your system of coordinates, but pseudovectors do, and that’s why they are a caveat worthy of note. This is usually not a problem as long as you stick within the same handed-ness in different system of coordinates, by avoiding such reflections.

There are several ways to actually compute the value of the cross product between two vectors, but the most common one and easier to remember is by finding the determinant of a particular matrix.

Curiously enough, the definition of a vector product returning another vector is unique to 3 and 7 dimensions. More general but similar objects can be defined for other dimensions.

In physics

The cross product is very useful in physics for describing things such as torques (the rotational equivalent of a force), angular momentum (the rotational equivalent of linear momentum), and magnetic forces on charged particles (which act perpendicular to both the velocity of the particle and the magnetic field).

The physical nature of the vector quantity in such cases as torque or angular momentum can be tricky to understand without the proper insight, which is something that is rarely addressed by physics text books.

It is common for students to get stuck to the idea that a vector, as represented by the arrow, points to the direction the force or whatever it is acting or “going towards”. But for angular momentum and torque, this intuition breaks down.

Angular momentum

The proper way to think about the vector for angular momentum is that the vector gives you an axis of rotation. The way the arrow is pointing tells you which of two possible ways the rotation is going (clockwise or counterclockwise, depending on your choice of coordinates and point of view). Using the right-hand rule (for a right-handed coordinate system), you can figure this out easily.

The magnitude of the vector is the actual magnitude of the momentum. So the vector is just a compact way to merge both bits of information on angular momentum in a single mathematical object. The consistency in all of the definitions is what makes it all work nicely, not coincidence.

Torque

The idea of a vector representing the axis and direction of rotation is the same here, but you can also, alternatively, consider it a plane in which the torque is acting on. The vector is normal to this plane.

But another tricky idea here is the dimensions of the torque vector. Remember that in physics, we say length, time and mass, for instance, are dimensions for a physical quantity. We say a meter, a second and a kilogram are units with the dimensions described before, respectively. This difference in terms (units vs. dimensions) is very important, and a lot of people don’t get it right the first time.

So, the dimensions of the torque vector are pretty weird: Newton-meter. A lot of students realize that this is the same thing as a Joule, which is a unit of energy. So why not say torque has the same dimension as energy, call it Joule, and get rid of the Newton-meter thing?

The answer is that while the dimensions match, the concepts don’t. Torque and energy are entirely different concepts, entirely different physical quantities, so they shouldn’t be treated the same even though their dimensions seem to match. But in my opinion, this difference is dogmatic if taken as Newton-meter vs. Joule, because it hides a very important detail.

I think torque makes more sense in units of Joules per radian. The radian is a dimensionless unit, which means it was hidden in there all along in our dimensional analysis. We were not comparing Joules with Joules, but Joules per radians with Joules! The radians bit comes from the fact torques act along an arc.

This is easy to see if we consider the work done by a torque τ: W = τθ, where θ is the angle the torque acted around, rotating an object. In this case, if you consider the dimensions of radians as non-disposable, you can easily see that it all works out.

Wrapping up

The cross product is a very handy tool for defining some more complicated physical quantities. It may seem arbitrary at first, but the reasoning behind its definition is mathematically sound and extremely useful in practice.

In order to fully appreciate it, one must first get rid of a few intuitions on what vectors represent in physics. Vectors can represent a lot of things that are not explicitly directional, as you first start getting used to them, so the sooner you abandon that intuition the better.

All the credit for the description and the image below goes to 1ucasvb.tumblr.com

The original post:

http://1ucasvb.tumblr.com/post/76812811092/given-two-vectors-in-three-dimensions-one-can

#mathematics #maths #science #physics

Given two vectors in three dimensions, one can define their vector or cross product as new vector, perpendicular to both original vectors, and with magnitude proportional to the sine of the angle from the first to the second vector.

In this animation, the cross product of two vectors a (blue) and b (red) are used, and their cross-product (vertical, in purple) is shown varying as the angle between both vectors changes.

As you can see, when both vectors are separated by a right angle (90° = π/2 radians or τ/4 radians), their cross product’s vector reaches a maximum length, and when both vectors are parallel, their cross product is zero. (Here, both vectors a and b are unit vectors, so the magnitude of their cross product doesn’t grow beyond 1 either)

Similar to the way the dot product can be used to find if two vectors are perpendicular, one can use the cross product to find out if two vectors are parallel. You just have to check if these products are zero in each case.

The mathematics

In mathematical notation, we write |v| or ||v|| as the norm or magnitude of a vector v. With that notation, we can say that |a × b| = |a| |b| sin(θ)

, where θ is the angle from a to b.

The cross product is said to be “anticommutative”, that is, the order used is important (so it is not commutative, in which case the order wouldn’t matter), and the “anti-” bit says that switching the order switches the sign of the product. Mathematically, a × b = -(b × a)

To be precise, the vector that results from the cross product is said to be a pseudovector, as it is not invariant through reflections: if you see your coordinate axes from a mirror, your right-handed coordinate system would become left-handed, so the definition of the vector breaks down. Vectors are extremely useful because they don’t depend on your system of coordinates, but pseudovectors do, and that’s why they are a caveat worthy of note. This is usually not a problem as long as you stick within the same handed-ness in different system of coordinates, by avoiding such reflections.

There are several ways to actually compute the value of the cross product between two vectors, but the most common one and easier to remember is by finding the determinant of a particular matrix.

Curiously enough, the definition of a vector product returning another vector is unique to 3 and 7 dimensions. More general but similar objects can be defined for other dimensions.

In physics

The cross product is very useful in physics for describing things such as torques (the rotational equivalent of a force), angular momentum (the rotational equivalent of linear momentum), and magnetic forces on charged particles (which act perpendicular to both the velocity of the particle and the magnetic field).

The physical nature of the vector quantity in such cases as torque or angular momentum can be tricky to understand without the proper insight, which is something that is rarely addressed by physics text books.

It is common for students to get stuck to the idea that a vector, as represented by the arrow, points to the direction the force or whatever it is acting or “going towards”. But for angular momentum and torque, this intuition breaks down.

Angular momentum

The proper way to think about the vector for angular momentum is that the vector gives you an axis of rotation. The way the arrow is pointing tells you which of two possible ways the rotation is going (clockwise or counterclockwise, depending on your choice of coordinates and point of view). Using the right-hand rule (for a right-handed coordinate system), you can figure this out easily.

The magnitude of the vector is the actual magnitude of the momentum. So the vector is just a compact way to merge both bits of information on angular momentum in a single mathematical object. The consistency in all of the definitions is what makes it all work nicely, not coincidence.

Torque

The idea of a vector representing the axis and direction of rotation is the same here, but you can also, alternatively, consider it a plane in which the torque is acting on. The vector is normal to this plane.

But another tricky idea here is the dimensions of the torque vector. Remember that in physics, we say length, time and mass, for instance, are dimensions for a physical quantity. We say a meter, a second and a kilogram are units with the dimensions described before, respectively. This difference in terms (units vs. dimensions) is very important, and a lot of people don’t get it right the first time.

So, the dimensions of the torque vector are pretty weird: Newton-meter. A lot of students realize that this is the same thing as a Joule, which is a unit of energy. So why not say torque has the same dimension as energy, call it Joule, and get rid of the Newton-meter thing?

The answer is that while the dimensions match, the concepts don’t. Torque and energy are entirely different concepts, entirely different physical quantities, so they shouldn’t be treated the same even though their dimensions seem to match. But in my opinion, this difference is dogmatic if taken as Newton-meter vs. Joule, because it hides a very important detail.

I think torque makes more sense in units of Joules per radian. The radian is a dimensionless unit, which means it was hidden in there all along in our dimensional analysis. We were not comparing Joules with Joules, but Joules per radians with Joules! The radians bit comes from the fact torques act along an arc.

This is easy to see if we consider the work done by a torque τ: W = τθ, where θ is the angle the torque acted around, rotating an object. In this case, if you consider the dimensions of radians as non-disposable, you can easily see that it all works out.

Wrapping up

The cross product is a very handy tool for defining some more complicated physical quantities. It may seem arbitrary at first, but the reasoning behind its definition is mathematically sound and extremely useful in practice.

In order to fully appreciate it, one must first get rid of a few intuitions on what vectors represent in physics. Vectors can represent a lot of things that are not explicitly directional, as you first start getting used to them, so the sooner you abandon that intuition the better.

All the credit for the description and the image below goes to 1ucasvb.tumblr.com

The original post:

http://1ucasvb.tumblr.com/post/76812811092/given-two-vectors-in-three-dimensions-one-can

#mathematics #maths #science #physics

1

Add a comment...

### Jason Hartgraves

Shared publicly -**What happens when a lightening bolt strikes a moving train? This.**

1

Add a comment...

In his circles

23 people

### Jason Hartgraves

Shared publicly -**Drawing a Triangle with a Compass.**

Join the Simple Science and Interesting Things Community and share interesting stuff!

https://plus.google.com/communities/117518490246975838002

http://24.media.tumblr.com/1476e5668bde05ed0fde899d17e37c92/tumblr_n6pv5vivB01sszkooo2_1280.gif

1

Add a comment...

### Jason Hartgraves

Shared publicly -What you're seeing here is a

The magnet falls straight through the tube without attaching to the inside of the tube because the electric current and magnetic field that are being made are equally distributed within the tube. This means that the magnet feels equally attractive forces from all directions, so it doesn't stick to just one area inside the tube.

The magnetic field within the copper tube does slow the magnet's fall but it wouldn't stop the magnet from falling all the way through. This is because without having the magnet moving inside the tube, there wouldn't be any electric current (

The Eddy current inducing effect that the neodynium magnet has mainly has to do with

Videos of the experiment and a short explanation of Lenz's law here: http://www.geekosystem.com/neodymium-magnets-copper-pipes/

Short YouTube video of what's going on here: Copper Pipe Magnet

Same YouTube video with an explanation of the demonstration: http://www.neatorama.com/2011/08/09/neodynium-magnets-fall-slowly-through-copper-pipe/#!Aa9wQ

**neodynium magnet**falling through a**copper tube**, though it falls very slowly for as long as it is in the tube. Since the magnet is moving within the copper tube, an**electric current**is formed. With the formation of this electric current, a magnetic field is also formed that starts to attract the magnet.The magnet falls straight through the tube without attaching to the inside of the tube because the electric current and magnetic field that are being made are equally distributed within the tube. This means that the magnet feels equally attractive forces from all directions, so it doesn't stick to just one area inside the tube.

The magnetic field within the copper tube does slow the magnet's fall but it wouldn't stop the magnet from falling all the way through. This is because without having the magnet moving inside the tube, there wouldn't be any electric current (

**Eddy Current**), which would also result in the lack of any magnetic field, causing the magnet to start falling again. While the magnet is inside the copper tube, even though it is falling and not physically attached to the insides of the tube, the tube as a whole will feel heavier. The total mass of the system doesn't change, but the weight does.The Eddy current inducing effect that the neodynium magnet has mainly has to do with

**Lenz's Law**. Wikipedia describes Lenz's law as, "An induced electromotive force (emf) always gives rise to a current whose magnetic field opposes the original change in magnetic flux." It's an explanation to how electromagnets follow**Newton's 3rd Law**and the**Law of Conservation of Energy**.Videos of the experiment and a short explanation of Lenz's law here: http://www.geekosystem.com/neodymium-magnets-copper-pipes/

Short YouTube video of what's going on here: Copper Pipe Magnet

Same YouTube video with an explanation of the demonstration: http://www.neatorama.com/2011/08/09/neodynium-magnets-fall-slowly-through-copper-pipe/#!Aa9wQ

1

Add a comment...

### Jason Hartgraves

Shared publicly -May be the reason for him to like so much golden rings...

1

Add a comment...

Story

Tagline

Building an empire

Bragging rights

I have bragging rights over the fact I have no bragging rights

Basic Information

Gender

Male

Apps with Google+ Sign-in

Drive thru wait time is always long. Park and walk in, you'll always get out faster.

Public - 9 months ago

reviewed 9 months ago

Swung by for Sunday brunch, what a mistake! We joined a group already there and it took at least 10 minutes before the waitress acknowledged us. We ordered drinks (bloody marys), they came in a timely manner but were below what you can get at a dennys in terms of quality. We probably saw our server two more times over 45 minutes before opting to leave.
STAY AWAY

Food: Poor to fairDecor: Poor to fairService: Poor to fair

Public - a year ago

reviewed a year ago

It is now a Slater's 50/50

Public - 2 years ago

reviewed 2 years ago