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Mark A. Ruiz Naranjo
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Mark A. Ruiz Naranjo

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Thanks for the reply i see it now!
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Mark A. Ruiz Naranjo

commented on a video on YouTube.
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Yes, exactly as zoss said, i don't see how the discrete relation is transitive, please clear this out can't find any discussion opn this on the internet
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mlbaker
 
It IS in fact transitive: every element is related only to itself. So if xRy and yRz, then we must have y=x and therefore z=y=x as well, in which case trivially xRz (i.e. xRx) is true. Equivalence relations and partitions are essentially the same thing, and the discrete relation corresponds to the partition where you place each element in its own "chunk"...
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Have him in circles
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Michael Dzec's profile photo
Jorge Garrido's profile photo
Elisa Conesa's profile photo
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Alvaro López's profile photo
Gauthier Moulins's profile photo
Manuel Herrera's profile photo
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