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Marián Varaga (Majo)
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Marián Varaga (Majo)

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Super aplikácia
 
Aplikácia Cerberus, ktorá sa zaoberá bezpečnosťou Android smartfónov a tabletov oslavuje svoje tretie narodeniny. 

Získajte bezplatnú licenciu len dnes!

http://www.mojandroid.sk/2014/04/25/cerberus-oslavuje-tri-roky-bezplatna-licencia-zadarmo
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Aplikácia Cerberus, ktorá sa zaoberá bezpečnosťou Android smartfónov a tabletov oslavuje svoje tretie narodeniny. Získajte bezplatnú licenciu len dnes!
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Marián Varaga (Majo)

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Zdravim, chcel by som pouzivat nejaky cloud na pc aj android, ale neviem si vybrat (skydrive, gdrive, dropbox alebo cokolvek ine). Co odporucate? A hlavne porovnavali ste ich niekto z hladiska ochrany dat? Viem, ze microsoft mazal fotky, potrebujem mat istotu(aspon ako taku), ze o data nepridem. Dakujem za odpovede
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Ju Rgen's profile photoRadim Šulák's profile photoMarek Bartok's profile photoPetr Husek's profile photo
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+Marek Bartok sám od sebe ti ho po pár dnech samozřejmě neodblokuje, to dá rozum, protože je to mimo jiné ochrana také tvých dat. Musíš požádat. Takže o žádná data nepřijdeš a po odblokování můžeš dál používat. Pokud si prečteš co ti píše po zablokování na přihlašovací stránce tak se to tam dozvíš.
Běžnému uživateli se to jen tak nestane.
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Marián Varaga (Majo)

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Christmas Trees, Science Style

It's always fun to invite scientists to your parties, as long as you remember that scientists sometimes think about trees differently than other people....

From the hidden text in the original xkcd comic (http://xkcd.com/835/):

Not only is that terrible in general, but you just KNOW Billy's going to open the root present first, and then everyone will have to wait whole the heap is rebuilt.

#ScienceSunday #HolidayScience #scisunABS
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Marián Varaga (Majo)

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The case of 18 and 81. My 8 year old son noticed that 9+9 = 18, and 9x9 = 81 (18 reversed) and was curious of other examples. I wondered if it holds in other bases.

In base 16:
F + F = 1E
F * F = E1

In base 8:
7 + 7 = 16
7 * 7 = 61

Does it hold in base B? That is:
[1] (B-1) + (B-1) = x*B + y
[2] (B-1) * (B-1) = y * B + x
 
For [1], we can move one of the -1's into the second expression
[1] (B) + (B -1 -1) = x*B + y
and see immediately that x is always 1 and y is always B-2.

In case [2], we have
[2] (B -1) * (B-1) = y * B + x
[2] B^2 - 2B + 1= y * B + x
factoring out a B
[2] (B - 2) * B + 1 = y * B + x

Again, we can see that y = B -2 and x = 1.

So in any base B, the highest digit added to itself is the same as the the number multiplied by itself and the digits reversed.

My son would be pleased by this proof, but I haven't taught him enough algebra yet.
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Marián Varaga (Majo)

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Interesting idea.
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Marián Varaga (Majo)

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An educational comics for non-programmers by +Jason Heeris. This is what it's like to be interrupted when coding.
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