Michelle Helen

+

5

6

5

6

5

Most incomplete math question ever.

Start a hangout

—————————————————————————————

248

248

178 comments

Michelle Helen

+

5

6

5

6

5

Most incomplete math question ever.

Kyle Wilson

+

4

5

4

5

4

B) 50% ?

Because there are 2 x 25% ?

Because there are 2 x 25% ?

Pierre Bontoux

+

7

8

7

8

7

blue?

It is an unknown.

Simon Cousins

+

4

5

4

5

4

Fish

Jaana Nyström

+

1

6

7

6

7

6

42

D- 25%

i lied it is B

c)

50%..as 25% comes two times that makes it a wrong choice. now you're left with only 2 of them. so 50%

Jon Blake

+

9

10

9

10

9

tht a 50 %

Same answer as: If 8 + 8 = 16 how much is a whole bunch of 9's?

if i chosse 25, Could be the probavility 75%?

Jon Blake

+

1

2

3

2

3

2

There is no answer to this question because if you chose randomly it would be a 25% chance but there are two 25%'s which make it a 50% chance but your chance of choosing 50% is a 1/4. ahhhhhhhh!

None of the above.

Though it would be more interesting if 37.5% were an option.

Though it would be more interesting if 37.5% were an option.

Jeremy Hill

+

5

6

5

6

5

It's not a math question, it's an IQ question. There are 4 answers. 2 answers are the same, leaving you with 3 possible answers. You would want to choose 60% since that's your best chance at being right, Vegas rules.

Sandro Pkhakadze

+

6

7

6

7

6

33.3333333.....% one of three

D- 25%

that being said, 25% is the correct answer, so that's a 100% kinda thing

Anilesh Alkari

+

2

3

2

3

2

33.33...........

Zeshan Ahmed

+

3

4

3

4

3

Answer is A or D its 25 % , it doesn't matter if 25% is two times, because, if you will go for maths and calculate than (2/4)*100 will make 50% as correct ansewer, and choosing of choice B, among the four choices is 25% again, so B is not the correct answer....

Jon Blake

+

1

2

1

2

1

+Zeshan Ahmed But if you choose A or D randomly.... that's not a 25% chance.....

It's a trick question

It's a trick question

B,100% sure.

50%

Mike Serafin

+

3

4

3

4

3

If the answer is 25% then your odds are 50%.

If the answer us 50% then your odds are 25%.

If the answer us 50% then your odds are 25%.

Depends on how you define the term answer. Is the answer the letter option or is it the value?

Katayoon Bit

+

1

2

1

2

1

its like 2 red ,one green and one black,knowing that the correct answer is red,ur chance to answer true is 50%

or we can say one answer is out because it repeated so we will have 1 out of three which is not in the answers!!!!!

Mhretab Kidane

+

3

4

3

4

3

33.3333.....%

C) 60%

At no time is any answer correct on it's own.

Patrick Steed

+

3

4

3

4

3

There are two 25% which means variables (choices) are three and would be 33.3333% but since "at random" is the question then 1/4 or 25% could be correct as well. It's a trick question though.

The real answer is you have a 25% chance if you choose B or C and a 50% chance if you choose A or D

B) 50%

Luís Davim

+

5

6

5

6

5

0%

baseless arguments on meaningless question.......

Sascha Nitka

+

2

3

2

3

2

33,33333%

BAYES Theorem... ;-))

BAYES Theorem... ;-))

yes, but, if you choose A or D, you have a 50%, so, you are on the B option... so... if you selected A or D, you select the option B too... so 75%... maybe... so so... :)

what are these options about a survey ? XD .............. with no idea about the question every option has equal probability of 1/4 for 4four options............

Justin Cooney

+

1

2

1

2

1

I'd agree there should be 33.3333% option since the 25% counts as one, so there are three possible choices

None of the above.

Trick question, not math!

Trick question, not math!

25% - 1/4 is correct, that means the probability of getting the correct answer is 25%

Jurij Udovč

+

3

4

3

4

3

isn't it 0%

Dave Varley

+

4

5

4

5

4

It's 0%. There is a 50% chance of picking 25%. A 25% chance of picking 50% and a 25% chance of picking 60%. None of those values match, so therefore there is 0% chance of picking the correct answer!

B)50%

Everyone knows C is the most common answer ... 60% MUST be accurate! :)

Kind of lame. 1+1 = a) 3 b) 0 c) 7 d) green. There is an answer, it's just not one of the choices.

100/3 %

this question is a paradox just like the "boy kills his grandfather" paradox

THERE IS NO ANSWER!!!!!

THERE IS NO ANSWER!!!!!

Ian Kirkpatrick

+

1

2

1

2

1

33.3333333%?

25% chance

50%,coz 2 in 4 are right

..50%-given the correct answer(s) lies in the choice

Ross Cullen

+

1

2

1

2

1

There is no question

50%

Daniel Harral

+

2

3

2

3

2

If you are choosing at random, and none of the options are correct, then the answer is 0% because it doesn't say that your answer needs to be one of the answers below. A better set of answers would be this: 20%, 40%, 50%, 20%, 0%. Then that answer is included and the cycle continues unbroken.

Kiril Kukareko

+

1

2

1

2

1

To understand recursion, you must first understand recursion

yes, it's right. the correct answer is 50%, so we have 25% of chance

This is truly an excellent example of a Thai university entrance question... No joke... Illogical, No Context, and Multiple possible correct answers!

none f the abv options

A is the answer and so is D.

This is multiple choice.

This is multiple choice.

+Romit Heerani chance is 50 % because a and d are same ...

*JUST KIDDING BELOW THIS LINE*

==============================

so...

there are 100 / 4 is chance between and we take

a=b=c=d= 1 then it is equal to

=x/a+b+c+d

=x/a+b+c+a (:. a = d)

=x/a+b+c ( 1 X 1 = s)

=x/3

= 75 %

==============================

so...

there are 100 / 4 is chance between and we take

a=b=c=d= 1 then it is equal to

=x/a+b+c+d

=x/a+b+c+a (:. a = d)

=x/a+b+c ( 1 X 1 = s)

=x/3

= 75 %

бред, ну а вообще 66,(6)%

Translate

let A+B+C+D=100%

A=25%

B=50%

C=60%

D=25%

A&D same

so

A=D

so

A+B+C=100% - D

so

A+B+C=75%

25% is correct answer

A=25%

B=50%

C=60%

D=25%

A&D same

so

A=D

so

A+B+C=100% - D

so

A+B+C=75%

25% is correct answer

my answer is 100%

Matthew Goffard

+

1

2

1

2

1

E) None of the above

they got 60% because if you have a 1/3 (3options) chance and 2 options that are the same 2/3=60%

Eric Grange

+

1

2

1

2

1

None of the answers are correct, so you have 0% chance of giving the correct answer.

Brandon Petaccio

+

4

5

4

5

4

The problem is that the text of each answer contradicts its *actual* percentage of total answers.

"25%" represents 50% of the possible answers.

"50%" represents 25% of the possible answers.

Thus, we enter an infinite loop while trying to answer the question: Choose "25%," and you realize there's a 50-50 shot at getting this answer. So the answer becomes 50%. But then you realize that this answer only represents a 25% shot at getting it correct. So you're back to "25%". And around the loop we go,*ad infinitum*.

"60%" is**just a monky wrench** thrown in there to give us a *nice even set of four answers* that each represent 25% of total possibilities. *That's why nobody can figure out how 60% might be calculated.* "60%" is the only random thing, here.

;-)

*The question calls on the answer to be determined by the selection*. Therefore, **it's impossible for any answer to be correct while the text contradicts the ***actual*** percentage that it represents**. Consider what would happen if, instead of "25%" appearing twice, it was "50%" that appeared twice:

(a) 50%

(b) 25%

(c) 60%

(d) 50%

That's a lot easier, isn't it? I suppose we could throw in a "(a) or (d)" option to shake things up a bit, heh heh ...

But since none of the answers in the illustration corresponds to its*actual* percentage, **there is no correct answer**. There should be a "none of the above" answer.

"25%" represents 50% of the possible answers.

"50%" represents 25% of the possible answers.

Thus, we enter an infinite loop while trying to answer the question: Choose "25%," and you realize there's a 50-50 shot at getting this answer. So the answer becomes 50%. But then you realize that this answer only represents a 25% shot at getting it correct. So you're back to "25%". And around the loop we go,

"60%" is

;-)

(a) 50%

(b) 25%

(c) 60%

(d) 50%

That's a lot easier, isn't it? I suppose we could throw in a "(a) or (d)" option to shake things up a bit, heh heh ...

But since none of the answers in the illustration corresponds to its

the correct answer is 25% either A or D..A tricky question but if u read 2ice or 3ice u will get the meaning of the question......

I think its A and B......................

B

very well conceived.

+Herbert Hawes III absolutely right!

+Jamal Romero

I don't agree with +Herbert Hawes III that the question allows us to gut all meaning from the possible answers.

We're not talking about something arbitrary. We're talking about which possible answer accurately describes its own percentage of availability. The correct answer is**none**, not "all".

I don't agree with +Herbert Hawes III that the question allows us to gut all meaning from the possible answers.

We're not talking about something arbitrary. We're talking about which possible answer accurately describes its own percentage of availability. The correct answer is

daniel hemphill

+

1

2

1

2

1

They shoulda made C) 0%

Of course there's no answer. But if we can afford some joking.... then the correct answer is:

E) 20%

E) 20%

It depends on what is the correct answer...

scenario 1: correct answer 25% ---- chances 50%

scenario 2: correct answer 50% ----- chances 25%

scenario 3: correct answer 60% ----- chances 25%

scenario 4: correct answer not listed -- chances 0%

scenario 1: correct answer 25% ---- chances 50%

scenario 2: correct answer 50% ----- chances 25%

scenario 3: correct answer 60% ----- chances 25%

scenario 4: correct answer not listed -- chances 0%

Woj Macaraan

+

1

2

1

2

1

This probably requires a philosopher rather than a mathematician to solve. My head just exploded.

+Woj Macaraan I think you mean a logician.

:-D

:-D

50% :D

this is a psychological question, which translates well: how safe these yourself?

50% if the answer is A or D

25% if the answer is B or C

25% if the answer is B or C

Micheal Banning

+

1

2

1

2

1

you got to take into acout that you are answering this question, at random, and wat percent you would be right, A and D are the same answer therefore those are wrong, if you had a 25% chance of answering this question right then all 4 answers would be different. Which then leaves you with 2 choices. B) 50% or C) 60% now that you only have 2 choices answering this question RANDOMLY you have a 50% chance of getting it right. so there fore the answer is B!

4 answers 1 right, 3 wrong... 25%

A and D are 25%... increase the chance to get the right.. so 25% is not the right answer... we fall back to the start... 4 answers 1 right, 3 wrong... 25% ... from my view... a endless story.

A and D are 25%... increase the chance to get the right.. so 25% is not the right answer... we fall back to the start... 4 answers 1 right, 3 wrong... 25% ... from my view... a endless story.

Ask Lisp

if you CHOOSE an answer

it is not RANDOM

it means you have thought about it

the answer does not matter as i choose it randomly

you cannot choose randomly if there is a choice

it is not RANDOM

it means you have thought about it

the answer does not matter as i choose it randomly

you cannot choose randomly if there is a choice

Yes but as you can only choose 1 answer from 4 (25%) and you have two answers having that number (A and D) then it means that you have 2 correct and 2 incorrect answers thus giving you 50% chance. So the answer is B. And boom goes the dynamite.

50%

Marco Amersfoort

+

3

4

3

4

3

If, and only if, an answer would be picked randomly, any of the answers would have been correct. The value of the answer would not have mattered if you picked it randomly. Your chance would have been 100%.

However, you're not picking your answer randomly. The option 100% is not there. Thus your chance is 0%, which is also not there. In fact, if you pick one of the answers, you're wrong 100% of the time. The only correct answer is no answer at all.

+Marco Amersfoort Did you actually read the question?

Marco Amersfoort

+

1

2

1

2

1

+Yury Chelomin No, I answer randomly.

The chance is 0% because the correct answer to the question is not one of the choices. I'm guessing this is actually an essay question and the space to answer is simply not in the picture.

it says choose at random but the question makes you think about the problem skools need this method

there is no question- there are 4 choices with no reason to pick any of them, therefor you have a 25% chance of getting it right by whatever arbitrary grader there is. And altho 25 is listed as both A and D, D must be correct because my name beings with a D ;)

oh I was close but the real answer is:

If the correct answer is A or D then a person has a 50% chance.

If the correct answer is B or C then they have a 25% since they are picking at random.

thank two apples A and D and 1 orange B and 1 pair D

and I think you will understand.

If the correct answer is A or D then a person has a 50% chance.

If the correct answer is B or C then they have a 25% since they are picking at random.

thank two apples A and D and 1 orange B and 1 pair D

and I think you will understand.

another answer is there is no correct answer since what makes the answer correct is undefined.

None of the ones shown, come on! It's a paradox

The real answer is 0% - or that you are just wrong, because if you guessed any of those you would be incorrect. If you choose an answer, your chances were obviously 100%, meaning you will ALWAYS be wrong.

The question is not well built because it does not specify clearly in which set of possible events the random choice is to be made ... !!!

For exemple, If you add "among the four following choices" ... obviously, the correct answer is not in those choices (none of them reflect the probability to get it) and so is 0 !!

To me, the fact that 25% appears two times in the choices is a strong clue that the question has to be understood that way ...

and notice that, this accepted, nothing in the question asserts that the correct answer is one the possible choices.

I find this logical puzzle interesting ... and would like to know if someone else confirms this reasoning.

For exemple, If you add "among the four following choices" ... obviously, the correct answer is not in those choices (none of them reflect the probability to get it) and so is 0 !!

To me, the fact that 25% appears two times in the choices is a strong clue that the question has to be understood that way ...

and notice that, this accepted, nothing in the question asserts that the correct answer is one the possible choices.

I find this logical puzzle interesting ... and would like to know if someone else confirms this reasoning.

If you say 0 you are wrong because you guessed 0 which means 100% and then we're back to 50% and we all know that doesn't work. The only way to win this one is to say 100% of the time and that means you will always be right, but I think this one is just designed to make you lose (the game).

I'm also basing this off of the fact that if you can choose 0%, you can obviously choose 100% as well, so why not just be right?

Oh, and you have to account for our inability to truly be random, because once you've read the questions and the answers, you will always have some bias behind your answer.

I'm also basing this off of the fact that if you can choose 0%, you can obviously choose 100% as well, so why not just be right?

Oh, and you have to account for our inability to truly be random, because once you've read the questions and the answers, you will always have some bias behind your answer.

AT RANDOM there is 25% chance. With calculated risk, 50%.

Random doesn't work here, because even if it was randomly chosen, 25% would also be 50%, and then it is 75%, but it can't be because that isn't an option. Once your answer is something that is not an option, the only thing left is to be right with a 100% answer.

trolled..!!

why the hell does that 60% doing there?

...

they could take it and add 75% instead!

and then add another option with 100%!

...

but that 60 shows that it's just a joke and nobody ever looked for an answer!

...

you have been "FOOL"ed all this time!!!!!!

...

they could take it and add 75% instead!

and then add another option with 100%!

...

but that 60 shows that it's just a joke and nobody ever looked for an answer!

...

you have been "FOOL"ed all this time!!!!!!

Tiago Dias

+

1

2

1

2

1

A: 0%. "What is the chance you will be correct?" This is the question. There are no wrong or correct answers, you are just choosing an answer without this jugment.

sandra paulin

+

1

2

1

2

1

If I choose randomly , how could I chose Considered in the same time ?!... (the main antithesis is in request)

and more Description :

It may look meaningful but it is meaningless in dept ...

and more Description :

It may look meaningful but it is meaningless in dept ...

The Question Ask you to do what it Ask you to Do not Do ...

It ask's do it Randomly but also it ask's to do it Considered ...

But the crazyness of this request is enough hidden and embedded to makes you go to solve it as a true request ... if it was not that much embedded that might make's just an "eehhh" and not any effort to solve it ..

It ask's do it Randomly but also it ask's to do it Considered ...

But the crazyness of this request is enough hidden and embedded to makes you go to solve it as a true request ... if it was not that much embedded that might make's just an "eehhh" and not any effort to solve it ..

I have a 50% chance of being 25% correct.

there is no right answer because there is no question here.

It is not giving anything to be right about. It is just saying something is right.

It is not giving anything to be right about. It is just saying something is right.

Our trusted and verified sources say: C

Good one indeed!. Its little tricky, still as we analyze what the question means:-

1. To answer any question with 4 options and one correct answer, the probability is 1/4 (25%).

2. In this question, there are two correct answers A and D (duplicate i.e 25%).

3. So, probability of randomly answering two duplicate correct answers will be 1/2 (50%).

4. So, the correct answer for this tricky question is B (50%).

there we go...

1. To answer any question with 4 options and one correct answer, the probability is 1/4 (25%).

2. In this question, there are two correct answers A and D (duplicate i.e 25%).

3. So, probability of randomly answering two duplicate correct answers will be 1/2 (50%).

4. So, the correct answer for this tricky question is B (50%).

there we go...

+Niranjan Arsid : Nope you are wrong. If B(50%) is the correct answer.

Then when I randomly pick the one among A B C D. 50% time I should be correct. i.e 2 options should have 50%.

But there is only 25% chance that I will be correct(25% chance to pick B).

So B is wrong.

Then when I randomly pick the one among A B C D. 50% time I should be correct. i.e 2 options should have 50%.

But there is only 25% chance that I will be correct(25% chance to pick B).

So B is wrong.

hemant kapare

+

1

2

1

2

1

and i thought my jokes were bad... 0_o

Better skip this one coz u still got 49 questions...

Time left: 5 mins

Time left: 5 mins

25

Adi Peshkess

+

2

3

2

3

2

It's really quite simple.

if the correct answer to the question is 25%, then both A and D are correct, in which case the probability of randomly picking a lettered choice with 25% as the answer is 50%. This is a contradiction, so the correct answer cannot be 25% If the correct answer is 50% or 60%, then the probability becomes 25% in either case, and again a contradiction. Therefore, the correct answer to the question is 0%, which is not an available choice. And so, the probability of randomly picking a lettered choice with 0% as the answer is still 0%, and this answer choice is self-consistent.

This is an exercise meant to illustrate the difference between a question that is solvable with math and logic and one that requires "outside the box" thinking. The idea that*"all answers are incorrect as written, and therefore with that answer-set, the problem is unsolvable"* illustrates the *"inside-the-box"* thinking that the correct answer must be one from the set provided. In fact, the question *"if you choose an answer* **[IMPLIED: listed below]** *to this question at random, what is the chance you will be correct?"* has a definitive answer: 0%. Because if you choose ANY of the given choices at all, you have a 100% chance of being wrong.

Even if you assume that you can choose any percentage at all, between 0% and 100%, allowing all fractions of a percent, the chance of it being correct is the limit as it approaches 0.

Now.... consider what happens if the answer choices are listed as follows:

a) 25%

b) 50%

c) 0%

d) 25%

if the correct answer to the question is 25%, then both A and D are correct, in which case the probability of randomly picking a lettered choice with 25% as the answer is 50%. This is a contradiction, so the correct answer cannot be 25% If the correct answer is 50% or 60%, then the probability becomes 25% in either case, and again a contradiction. Therefore, the correct answer to the question is 0%, which is not an available choice. And so, the probability of randomly picking a lettered choice with 0% as the answer is still 0%, and this answer choice is self-consistent.

This is an exercise meant to illustrate the difference between a question that is solvable with math and logic and one that requires "outside the box" thinking. The idea that

Even if you assume that you can choose any percentage at all, between 0% and 100%, allowing all fractions of a percent, the chance of it being correct is the limit as it approaches 0.

Now.... consider what happens if the answer choices are listed as follows:

a) 25%

b) 50%

c) 0%

d) 25%

33.3333... %

Yes, it it is 33.3333......%

Zlatko and Devang: read the post before yours... You have zero chance of picking 33.3333.... %, so that's not right.

salman salman

+

2

3

2

3

2

there are 4 option

==> 100% : 4 = 25%

its option A and D...

so that you have 2 probably correct option of total 4

==> 2/4 = 1/2 = 50%

then you have to choose..................B) 50%

BUT ANYWAY........DON'T THINK ABOUT IT SO HARD..THE TRICK (KEY WORDS) IS:

"choose an answer at random"

so that just choose an option..don't worry if its correct or even wrong...

HUAAAAHAHAHAHA....:D

==> 100% : 4 = 25%

its option A and D...

so that you have 2 probably correct option of total 4

==> 2/4 = 1/2 = 50%

then you have to choose..................B) 50%

BUT ANYWAY........DON'T THINK ABOUT IT SO HARD..THE TRICK (KEY WORDS) IS:

"choose an answer at random"

so that just choose an option..don't worry if its correct or even wrong...

HUAAAAHAHAHAHA....:D

+salman salman However, If the answer is 50%, then that means the answer is B.

But, then that makes it only a 25% chance of picking the right answer, again making the answers A and D, creating an infinite loop of logic.

Because of this, I am choosing C. :P

But, then that makes it only a 25% chance of picking the right answer, again making the answers A and D, creating an infinite loop of logic.

Because of this, I am choosing C. :P

If 60% is right wouldn't that change the answer to 25% percent again?

The question doesn't mention that one of the values is correct.

A, B and D are chosen to form a loop. Because of the loop this three possible answers become wrong. C is there to give a fourth wrong answer.

Try it with other values.

E.g. A= 5%, B= 11%, C= 4%, D= 5%

In this case no one would be correct so there is an chance of 0% to picking the right answer.

A, B and D are chosen to form a loop. Because of the loop this three possible answers become wrong. C is there to give a fourth wrong answer.

Try it with other values.

E.g. A= 5%, B= 11%, C= 4%, D= 5%

In this case no one would be correct so there is an chance of 0% to picking the right answer.

Most random variables are not uniformly distributed. Otherwise games of chance would be boring.

Consider the roll of three binary dice as the random means of selection (or flipping three coins). A sum of 0 yields (a), 1 yields (b), 2 yields (c) and 3 yields (d). Sums of both 0 (000) and 3 (111) each occur 1/8 of the time, while 1 (001,010,100) and 2 (011,101,110) each occur 3/8 of the time. There is a 25% chance of picking either (a) or (d) by this method of random choice, thus both those answers are correct.

When confronted with a problem, make reasonable assumptions that allow the problem to be solved.

Consider the roll of three binary dice as the random means of selection (or flipping three coins). A sum of 0 yields (a), 1 yields (b), 2 yields (c) and 3 yields (d). Sums of both 0 (000) and 3 (111) each occur 1/8 of the time, while 1 (001,010,100) and 2 (011,101,110) each occur 3/8 of the time. There is a 25% chance of picking either (a) or (d) by this method of random choice, thus both those answers are correct.

When confronted with a problem, make reasonable assumptions that allow the problem to be solved.

PATRIK Pekarcik

+

1

2

1

2

1

maybe i'm **over thinking** this but when 25% is correct(at the beginning) and we have 4 options (2 times 25%) than 50% is correct answer too so we have 3/4 correct answers so the best would be 75% but we do not have this answer ..... but we can get into cycle 75% will be correct too ... bad thinking :/

4 choices >>>>> 25%..... 2 of them are the same >>> still 25%

what?

The answer is 33.3333%. I thought it this way. For any question which has four options but the A and D are the same, you are actually having only 3 choices. So the chance you pick the right one is 1/3, no matter what the question is.

ben miled bilel

+

1

2

1

2

1

There is no answer to this question because if you chose randomly it would be a 25% chance but there are two 25%'s which make it a 50% chance but your chance of choosing 50% is a 1/4

Anjani Gupta

+

1

2

1

2

1

50%

there are 2 outcomes there fore 50%

50%

25%

no one... 33%

n why is dat???

B)

A :)

I have to say B. reasoning on the matter. What is the chances that you will get the answer CORRECT! On multiple choice questions, if the same answer appears twice typically it is the wrong answer. So that narrows it down logically to 2 answers. B or C. which is 1 of 2. or 1/2 which is 50%. This isn't a math question people. Just because numbers are incorporated, doesn't automatically make it math. It is logical reasoning. Sure there are 4 answers, but you can automatically wipe 2 of them out (A and D). Come on people this is first grade.

Except that... You have on chance on 4 to choose 50%... So the godd answer would be 25%... But there"s 2 of them ! So there's 50% to choose A or D... So the good answer is B... But...

25

With the way it's worded, most people will think 1 answer out of 4 is 25% and choose A or D, the slightly more intelligent people will notice there's 2 25% so they think the answer is 50% (B), only those more intelligent (or less hasty) than that will notice they were just tricked... It's asking the chance of being correct given a random answer, but we don't know what "correct" is. If the "correct" answer is 25%, then the answer is 50%, in which 50% would then be the correct answer, which in that case would be 25%. God damn, it's like inception. It blows your mind!

It's easy, all answers are wrong.

The problem is that the question changes depending on the answer. It's kind of like this: This statement is untrue.

gud 1

Hira Gulroo

+

1

2

1

2

1

50% chance if i chose 25 % as answer but if i chose 60 or 50 probablity may decreases by .25

no matter your answer your wrong. if u pick a or d (25%) the answer would be 50%. if you pick 50% the answer would be 25%. same with 60%.... you cannot get this right

1/3

100% sure that the answer is B....:) Good Luck

zakir syed

+

1

2

1

2

1

0% Bcoz there is no Question at all. :-P

There are 4 choices. A random choice would be one out of these 4 so there is 25% chance of choosing any one answer. Now 25% appears twice, or half times = 50%. So the probability of being correct, that is choosing 25% (A and D) is half or 50%. Answer : 50%

its a paradox because if the answer was "B) 25%" it would still be 1 in 4 which is 25% or the A and D choices which if are the correct answers would be 1 in 2 (answer D) then the cycle continues.

60%

50%

50%

50%

then it would become 75%

Most are giving an answer to A,B,C or D but first before you give propabilities you have to know the answer (to the question) but how can you know an answer to something when you don't even know the question?

This is the flaw - There is no real question, therefore there is no real answer - Therefore there can not be propabilities regarding the chances of A,B,C or D holding the correct answer.

In an ideal world WITH A REAL QUESTION this is how this would work.

1. First we need to isolate the actual question.

2. Then to that question (with out looking at the A,B,C,D options at this point in time), work out the answer.

3. Then once we know the answer look to see if the answer is in the A,B,C,D options.

4. If the answer that we came up with in step 2 matches (A -25%) then the chances of choosing the correct answer out of ABCD is 50% because (D) has the same answer so in this case the answer is 50%.

5. If the answer that we came up with in step 2 matches (B - 50%) then the chances of choosing the correct answer out of ABCD is 25% so in this case the answer is 25%.

6. If the answer that we came up with in step 2 matches (C - 60%) then the chances of choosing the correct answer out of ABCD is 25% so in this case the answer is 25%.

7. If the answer that we came up with in step 2 matches (D - 25%) then the chances of choosing the correct answer out of ABCD is 50% because (A) has the same answer so in this case the answer is 50%.

8. If the answer in step 2 is not contained with in A, B, C or D then in this case the answer is 0%.

So the propabilities will vary - Either 50% (A and D) or 25% (B and C) or 0% if the answer in step 2 is not with in the answers in ABCD.

The actual answer in STEP 2 will determine whether you get a 25% or 50% or 0% chance at choosing the correct answer with in ABCD.

This example above is how it should have worked.

BUT HERE IS THE KICKER - IN ORDER TO HAVE THE ANSWER (IN STEP 2) - YOU HAVE TO HAVE A SOLID DEFINABLE QUESTION TO ANSWER IN THE FIRST PLACE.

If you can't write down the single question and provide a single answer to it, while ignoring the ABCD list at this point in time - (that doesn't come in to it untill you know the answer to the question)

THEN YOU CAN'T WORK OUT THE PROPABILITIES OF CHOOSING THE CORRECT ANSWER BECAUSE FIRST YOU MUST HAVE AN ANSWER TO WORK WITH IN THE FIRST PLACE AND FOR THAT YOU NEED A SOLID DEFINABLE QUESTION.

DK

This is the flaw - There is no real question, therefore there is no real answer - Therefore there can not be propabilities regarding the chances of A,B,C or D holding the correct answer.

In an ideal world WITH A REAL QUESTION this is how this would work.

1. First we need to isolate the actual question.

2. Then to that question (with out looking at the A,B,C,D options at this point in time), work out the answer.

3. Then once we know the answer look to see if the answer is in the A,B,C,D options.

4. If the answer that we came up with in step 2 matches (A -25%) then the chances of choosing the correct answer out of ABCD is 50% because (D) has the same answer so in this case the answer is 50%.

5. If the answer that we came up with in step 2 matches (B - 50%) then the chances of choosing the correct answer out of ABCD is 25% so in this case the answer is 25%.

6. If the answer that we came up with in step 2 matches (C - 60%) then the chances of choosing the correct answer out of ABCD is 25% so in this case the answer is 25%.

7. If the answer that we came up with in step 2 matches (D - 25%) then the chances of choosing the correct answer out of ABCD is 50% because (A) has the same answer so in this case the answer is 50%.

8. If the answer in step 2 is not contained with in A, B, C or D then in this case the answer is 0%.

So the propabilities will vary - Either 50% (A and D) or 25% (B and C) or 0% if the answer in step 2 is not with in the answers in ABCD.

The actual answer in STEP 2 will determine whether you get a 25% or 50% or 0% chance at choosing the correct answer with in ABCD.

This example above is how it should have worked.

BUT HERE IS THE KICKER - IN ORDER TO HAVE THE ANSWER (IN STEP 2) - YOU HAVE TO HAVE A SOLID DEFINABLE QUESTION TO ANSWER IN THE FIRST PLACE.

If you can't write down the single question and provide a single answer to it, while ignoring the ABCD list at this point in time - (that doesn't come in to it untill you know the answer to the question)

THEN YOU CAN'T WORK OUT THE PROPABILITIES OF CHOOSING THE CORRECT ANSWER BECAUSE FIRST YOU MUST HAVE AN ANSWER TO WORK WITH IN THE FIRST PLACE AND FOR THAT YOU NEED A SOLID DEFINABLE QUESTION.

DK

I think the answer is 40%. And it might not add up to be 100% which is regular simple math, however, this is considered to be weighted percentage question. Good luck in figuring this out! :) (But once you use simple logic by disregarding 25% answers because they are the same you left with 50% chance, maybe world is that simple now)

well the anser would be 25% cuz there are 4 posible ansers but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25% but the anser 25% is there twice so its 50 % but theres only one 50% so the anser is 25%. i'm confuzled

Fantastic!

1/3 - one third in English :-)

right 33.33%,three distinct answers

60%

E) 100%

E) It's a contradiction, there's no good answer

No Solution. 'No Solution' is generally reserved for equations but I think it applies here.

33%.

50% of course...

50%

Answer is 60% don't think about it. It tells you. It is a question of psychological value not IQ. The last response thought of based on first instinct.

Add a comment...