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Consider the function of the from. We shall the check the of the given function at the point x=4 . To check the continuity of the given function we follow the three steps. (i) Value of Function at given Point: We have given value of function at x=4 is equal to 0 .
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JANET EMMANUEL's profile photo
 
It nice seeing this,pls can u treat calculus
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In this tutorial we shall discuss an example to evaluating limits involving cubic expression, in most of the cases if limit involves cubic expression and we can factorize by using method of synthetic division. Let us consider an example which involve cubic expression. limit _ {x->1}(x^(3)+x ...
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In this tutorial we shall discuss an example of limit which involves quadratic function, and to find the value of limit we shall factorize the quadratic first and then solve it for the existence of limit. Let us consider an example which involve quadratic expression. limit _ {x->-1}(x^(2)+ ...
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Let us consider the relation. limit _{x->0} (a^(x)-1. Let y=a^(x)-1 , then 1+y=a^(x) , we have. Consider the relation. 1+y=a^(x). Taking logarithm on both sides, we have. ln (1+y)= ln a^(x) ln (1+y)=x ln a x=( ln (1+y))/( ln a). Also limit _{x- >0}y= limit _{x-> . This shows that y- >0 as x->0 .
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Let us consider the function f defined by the equation f(x)=(2x^(2))/(x^ . Let x take on the values 0, -1, -2, -3, -4, -5, -10, -100, -1000 etc, allowing to decreasing through negative values without bound. In this case, we say that x is approaching negative infinity and write x->- infinity ...
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A physical object that is moving cannot immdeiately disappear at some point and again appear from some where else to continue its motion. Thus, we perceive the path of a moving object as a single, unbroken curve without gaps, jumps or holes. Such curves can be described as continuous.
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In this tutorial we shall discuss an example to evaluating limits involving function with nth power of variable, in most of the cases if limit involves nth power variable expression and to solve using binomial theorem. Let us consider an example which is. limit _{x->a}(x^(n)-a ...
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Let us consider the relation. (1+(1)/(x))^(x). We shall prove this formula with the help of binomial series expansion, we have. (1+(1)/(x))^(x)= Taking limit as x-> infinity both sides, we get. limit _{x-> infinity }(1+(1)/(. Applying limits we have. limit _{x-> infinity }(1+(1)/( ...
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Let us consider the function f defined by the equation f(x)=(2x^(2))/(x^ . Let x take on the values 0, 1, 2, 3, 4, 5, 10, 100, 1000 etc, allowing increasing without bound. The corresponding function values are given in the given table below.
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