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Brent DeJong
Works at Shoreline Containers
Attends Grand Valley State Unviversity
71 followers|14,391 views
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Brent DeJong

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We know where we are now, which is tragic.
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Brent DeJong

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So, you're going to get a value that's a multiple of 4. The probability that the number of cards you're holding is the number you first calculate is 1/4, or 25%. 
So: if you're holding x cards, how many times do you have to add or subtract? Let's find out!
1 = 40 - 13*3......14 = 40 - 13*2.......27 = 40 - 13*1..........40 = 40
2 = 28 - 13*2......15 = 28 - 13*1.......28 = 28....................41 = 28 + 13*1
3 = 16 - 13*1......16 = 16................29 = 16 + 13*1..........42 = 16 + 13*2
4 = 4 ................17 = 4 + 13*1.......30 = 4 + 13*2 ...........43 = 4 + 13*3
5 = 44 - 13*3......18 = 44 - 13*2......31 = 44 - 13*1 .......... 44 = 44
6 = 32 - 13*2 .....19 = 32 - 13*1 .....32 = 32 ....................45 = 32 + 13*1
7 = 20 - 13*1 ......20 = 20...............33 = 20 + 13*1 .........46 = 20 + 13*2
8 = 8 .................21 = 8 + 13*1 .....34 = 8 + 13*2 ...........47 = 8 + 13*3
9 = 48 - 13*3 ..... 22 = 48 - 13*2 ....35 = 48 - 13*1 ...........48 = 48
10 = 36 - 13*2 ....23 = 36 - 13*1 ....36 = 36 .....................49 = 36 + 13*1
11 = 24 - 13*1 ....24 = 24 ..............37 = 24 + 13*1 ..........50 = 24 + 13*2
12 = 12 .............25 = 12 + 13*1 ....38 = 12 + 13*2 ..........51 = 12 + 13*3
13 = 0 + 13*1 ....26 = 0 + 13*2 ......39 = 0 + 13*3 ........... 52 = 0 + 13*4
So, if you're holding between 10 and 38 cards, you add or subtract 13 no more than 2 times. If we don't count adding straight thirteens to 0, the upper bound increases from 38 to 42. 

I conclude that optimal range is to leave at least 10 cards on the table and pick up at least 10 cards.
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Brent DeJong

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There's no psychological challenge for the robot :(
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Brent DeJong

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This is pretty cool :) Shows the physics of 60-Hz electricity pretty well :)
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Brent DeJong

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triple negative = single negative lol
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Brent DeJong

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My approach was: 136/4 = (100+36)/4 = 25+9 = 34. Average is 34. OK. 31, 33, 35, 37.
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Brent DeJong

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All twisted up.... never seen the dude like this :-P
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Have him in circles
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Brent DeJong

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For every state of one cube, there is exactly one state of the other cube in this puzzle, are there not? Then this puzzle has just as many states as the original rubik's cube: 12!*8!*3^12*2^8/12. Perhaps I have missed something; if so, enlighten me.
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Actually, now I see it's not quite as simple as I had thought. Pay attention to the interaction between the green and blue faces, and you'll see that while one green face turns it does nothing to the blue face on one cube, but something to the blue on the other. Then, if g is a ccw turn of the green face on one cube, and b a ccw turn of the blue face on the same cube, gbgbgbgb will result in one cube being solved but not the other.
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Brent DeJong

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yes
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Brent DeJong

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This is recent? I saw this the first time I looked at Pascal's triangle... but then, I suppose the proof would take some time to develop.
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Brent DeJong

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2 es el más raro porque es el único que es par? bueno, 3 es el único igual a 0 mod 3, 5 el único igual a 0 mod 5.... todos son iguales de raro pensando así :P
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n solo esta definido para los enteros, pensé que era obvio. Hablar de pares e impares considerando los racionales tales que estos no estén contenidos en los enteros  no tiene sentido(lo digo por tu sustitución de n= 1/2), lo siento falto colocarlo xD, con esto espero que le veas el sentido....  todos los números de la forma 2n tales que n pertenezca a los enteros son pares, y los de la forma 2n+1 tal que n pertenezca a los enteros son impares.
Yo estoy de acuerdo contigo, pero ¿ No te parece curioso que todos los otros primos puedan escribirse así 2n+1  y justo el primo 2 no ?
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Brent DeJong

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" Vai repetir a frase..." GANHOU!! kkkkkkkkkkkkkkkkk
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Have him in circles
71 people
Elmer Victor Laura Quiñones's profile photo
Cindi DeJong's profile photo
Silvana Ramos's profile photo
Monica Ophoff's profile photo
imran saba i s's profile photo
Keith Van Overloop's profile photo
Becky Hanemaayer's profile photo
Ryan Griess's profile photo
Jeremy DeJong's profile photo
Work
Occupation
Student
Skills
Bilingual - Spanish. Good with mental math. can think critically and abstractly.
Employment
  • Shoreline Containers
    Summer help, 2012 - present
    Part time when school's in and full time when school's out, this job is supposed to remind me why I'm in school. It doesn't do its job that well except at paycheck time.
  • Student, 1997 - present
  • Employment Solutions
    Temp, 2010 - 2013
Basic Information
Gender
Male
Other names
De Jong
Story
Tagline
Twitter @dejongbrent
Introduction
6'3 redhead.
Education
  • Grand Valley State Unviversity
    Spanish for secondary education, 2010 - present
  • CCHS
    2007 - 2010
  • HCS
    1997 - 2007
Links
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